PURPOSE
The objective of this experiment is to make an experimental measurement of Avogadro's number using an electrochemical technique.
PRINCIPLES
The atomic mass of an element in grams is equal to one mole of the element. Chemists used this definition of a mole long before they were able to measure the masses of individual atoms or had the means to count atoms. The determination of Avogadro's number, which is the number of particles in a mole, required the development of accurate and suitable measuring devices that were not in existence until the early part of the twentieth century. The mole is considered a fundamental unit has been adopted into the SI system as a basic unit of quantity. In this experiment we will make a careful measurement of electron flow, amperage, and time to obtain the number of electrons passing through the electrochemical cell. The electron flow, in amperes, is usually referred to as the current. The number of atoms in a weighed sample can be related to the number of electrons used and from that the value called Avogadro's number can be calculated.
Avogadro's number can be determined in a number of different ways. This experiment will use an electrochemical process called electrolysis. The experimental setup for this process is called an electrolytic cell.
An electrolytic cell is made up of the following:
In the drawing of the electrolytic cell both electrodes are copper and the
electrolyte is 0.5 M H2SO4. In the course of the
electrolysis, the copper electrode (the anode) connected to the positive pin of
the power supply loses mass as the copper atoms are converted to copper ions.
This loss of mass is visible to the eye after a while as pitting of the surface
of the metal electrode. Also the copper ions, Cu2+ , produced,
immediately pass into the water solution and impart a blue tint to the water. At
the same time at the other electrode, the cathode, hydrogen gas, H2,
is liberated at the surface through the reduction of hydrogen ions,
H+, in the aqueous sulfuric acid solution. The reaction is
2 H+ + 2
electrons -> H2 (gas).
It is also possible to
collect the hydrogen gas produced and use it to calculate Avogadro's number.
However, in this experiment we will base calculation of Avogadro's number on
loss of mass of the copper anode.
EXAMPLE
Georgia P. Dunwoody, an industrious coed, made the following measurements in the chemistry laboratory.
Anode mass lost: 0.3554 grams (g) Current(average): 0.601 amperes (amp)
Time of electrolysis: 1802 seconds (s)
Note: one ampere = 1 coulomb/second or one amp.s = 1 coul
charge of
an electron 1.602 x 10-19coulomb
Step 1. Find the total charge passed through the circuit.
(0.601
amp)(1coul/1amp-s)(1802 s) = 1083 coul
Step 2. Calculate the number of electrons in the electrolysis.
(1083 coul)( 1 electron/1.6022 x 1019coul) = 6.759 x
10 21electrons
Step 3. Determine the number of copper atoms lost from the anode. Recall the
electrolysis process consumes two electrons per copper ion formed. Therefore the
number of copper(II) ions formed is half the number of electrons.
Number of
Cu+2 ions = ˝ number of electrons measured , namely,
(6.752 x 10 21 electrons)(1 Cu+2 / 2 electrons) =
3.380 x 10 21 Cu+2 ions
Step 4. Calculate the number of copper ions per gram of copper from the
number of copper ions above and the mass of copper ions produced. The mass of
the copper ions produced is equal to the mass loss of the anode. ( The mass of
the electrons is so small that it is negligible in this measurement, therefore
the mass of the copper (II) ions is the same as copper atoms.)
Thus:
mass loss of electrode = mass of Cu+2 ions = 0.3554 g
3.380 x 10 21 Cu+2 ions / 0.3544g = 9.510 x
10 21 Cu+2 ions/g
= 9.510 x 10 21 Cu atoms/g
Step 5. Calculate the number of
copper atoms in a mole of copper, 63.546 grams.
Cu atoms
/mole of Cu=(9.510 x 10 21 copper atoms/g copper)(63.546
g/mole copper)
= 6.040 x 10 23 copper atoms/mole of copper
This is the student's measured value of Avogaro's number.
Step 6. Calculate the percent error.
Absolute
error: |6.02 x 10 23 - 6.04 x 10 23 | = 2 x 10
21
Percent error: (2 x 10 21 / 6.02 x 10 23)(100) = 0.3 %
PROCEDURE
Obtain two copper electrodes. It is may be necessary to first clean the anode before any measurements are taken. If needed, immerse the anode in 6 M HNO3 in the fume hood for 2 to 3 seconds. Remove the electrode promptly. Nitric acid is a powerful oxidizing agent as well as a strong acid and it will destroy the anode quickly if not removed. Do not touch the electrode with your fingers. Dip the electrode in a beaker of clean tap water then dip the electrode in the beaker labeled alcohol. Let the electrode dry on a paper towel. When the electrode is dry, weigh it carefully on the analytical balance to the nearest 0.0001 gram.
See the drawing for the arrangement of the apparatus. The electrolytic solution in the 250-mL beaker is 0.5 M H2SO4. Caution-this solution is corrosive and will damage skin and clothing on contact. Before making any connections be sure the power supply is off and unplugged. The power supply must be connected to the ammeter in series to the electrodes. The correct sequence requires the positive pole of the power supply be connected to the anode of the first cell. The cathode is next connected to the positive pin of the ammeter and negative pin of the ammeter is connected to the anode of the second cell. Finally the cathode of the second electrolytic cell is connected to the negative post of the power supply. Have your apparatus approved by the instructor before you turn on the power! When the apparatus is approved, plug in the power supply. Make sure the power supply is in the off position. Accurate measurements of the time in seconds and the current in amperes are essential for good results. The amperage should be recorded at one minute (60 sec) intervals. The amperage may vary over the course of the experiment due to changes in the electrolyte solution, temperature, or position of the electrodes. The amperage used in the calculation should be an average of the readings taken. The current should flow a minimum of 1020 seconds(17.00 minutes). Measure the time to the limit of the timing device. This should be to the nearest second or fraction of a second. After 1020 seconds turn off the power supply record the last amperage value and the time.
Now that the electrolysis has stopped you will need to retrieve the anode from the cell, dry it, and weigh it on the analytical balance. DO NOT WIPE THE ANODE WITH A TOWEL. Dry it as before by immersing it in alcohol and allowing it to dry on a paper towel. If you wipe it you will remove copper from the surface and invalidate your work.
Repeat the experiment if time is available. Use the same electrodes.
DIAGRAM OF APPARATUS FOR ELECTROLYSIS
ELECTROLYSIS DATA
ELECTRODE MEASUREMENTS
Trial 1 Trial 2
Mass of anode before electrolysis __________ g __________ g
Mass of anode after electrolysis __________ g __________ g
Mass loss of
anode
__________ g __________ g
-------------------------------------------------------------------------------------------------------------------
TIME-AMPERAGE MEASUREMENTS
Trial 1 Trial 2 Trial 1 Trial 2
Time
Current
Current
Time
Current
Current
(min)
(amps)
(amps)
(min)
(amps) (amps)
0 _____ _____ 10 _____ _____
1 _____ _____ 11 _____ _____
2 _____ _____ 12 _____ _____
3 _____ _____ 13 _____ _____
4 _____ _____ 14 _____ _____
5 _____ _____ 15 _____ _____
6 _____ _____ 16 _____ _____
7 _____ _____ 17 _____ _____
8 _____ _____ 18 _____ _____
9 _____ _____ 19 _____ _____
Average current:
_____
_____
SUMMARY OF DATA AND RESULTS
Trial 1 Trial 2
Total time of electrolysis (seconds) __________ __________
Average current during electrolysis (amperes) __________ __________
Total charge measured (coulombs) __________ __________
Number of electrons passed __________ __________
Number of Cu2+ ions generated __________ __________
Number of Cu2+ ions/gram Cu metal (Cu2+/g Cu) __________ __________
Avogadro's number (from your measurements) __________ __________
Avogadro's number ( true or accepted value) __________ __________
Absolute error in measured value __________ __________
Relative % error in measured
value
__________ __________
Determination of Avogadro’s Number
Pre-Lab Questions:
1. What are oxidation and reduction?
2. What are an anode and a cathode?
3. What is an electrolyte? What is the nature of electrical
current in a liquid solution?
Is
it flow of electrons or flow of ions?
4. Which of the following variables strongly influence the
current magnitude you observe? (a) Electrical Voltage
applied between two Cu electrodes, (b) Mass
of the Cu anode, (c) Mass of the Cu cathode, (d) Volume of the
electrolyte solution, (e) Concentration of
the electrolyte solutions, (f) Temperature of the solution, (g) the
Atmospheric pressure, (h) Surface area of the
electrodes that are in contact with the electrolyte solution.
5. Find the total positive charges (in coul) of all of the
positive ions contained in the 150mL of 0.5 M H2SO4
solution. Find the total negative
charges from all of the negative ions as well.
6. An average current of 0.435 was passed for 19 min to oxidize
and dissolve a Cu electrode. An intitial mass of
the electrode, which was 21.6961 g, decreased
to 21.5273 g as a result. What is the value of the Avogadro’s
Number according to this data? What is the
relative % error in this measurement?
Post-Lab Questions:
1. The currents you observed may not remain constant even though
the electrolysis is performed at a constant
potential(voltage) applied between two
electrodes..
If it increases, why does it increase? If it decreases, why does it decrease?
2. If the electrolysis is performed for 1020sec (17min) sec with
an average current of 0.486 amp at a constant
potential of 1.00 V, how much
electrical energy (kJ) was spent for the electrolysis?
3. Uncertainty in which of the following measurements are NOT
important in this experiment? (a) Mass of the
electrodes, (b) Average current, (c) Time of the electrolysis, (d) Volume of the
electrolyte used, (e)
Concentration of the
electrolyte .